What is the asymptotes of f(x)=(x^2-4)/(x^2-2x-8) ?

The asymptotes of f(x)=(x^2-4)/(x^2-2x-8) is Vertical: x=4,Horizontal: y=1

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asymptotes of f(x)=(x^2-4)/(x^2-2x-8)

asymptotes

f (x) = \frac{x ^{2} - 4}{x ^{2} - 2 x - 8}

Vertical : x = 4, Horizontal : y = 1

Solution steps

Vertical asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 2 x - 8} : x = 4

Horizontal Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 2 x - 8} : y = 1

Slant Asymptotes of

\frac{x ^{2} - 4}{x ^{2} - 2 x - 8} :

None

Vertical : x = 4, Horizontal : y = 1

f (x) = \frac{ln ( x )}{x ^{13}}

2 x^{2} + 15 x + 7

f (x) = \frac{4 x ^{2}}{x ^{2} - 9}

f (x) = ∣ x + 4 ∣

f (x) = \frac{x - 1}{3} + 1

What is the asymptotes of f(x)=(x^2-4)/(x^2-2x-8) ?
The asymptotes of f(x)=(x^2-4)/(x^2-2x-8) is Vertical: x=4,Horizontal: y=1