What is the domain of f(x)=(4x^2)/(x^2-9) ?

The domain of f(x)=(4x^2)/(x^2-9) is x 3

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domain of f(x)=(4x^2)/(x^2-9)

domain

f (x) = \frac{4 x ^{2}}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = ∣ x + 4 ∣

f (x) = \frac{x - 1}{3} + 1

f (x) = x^{2} + 1

f (x) = - \frac{1}{2} cos (2 x - 2 π)

y = - 4 x + 2

What is the domain of f(x)=(4x^2)/(x^2-9) ?
The domain of f(x)=(4x^2)/(x^2-9) is x<-3\lor-3<x<3\lor x>3