What is the midpoint (1/8 ,-4/9),(-5/2 , 5/2) ?

The midpoint (1/8 ,-4/9),(-5/2 , 5/2) is (-19/16 , 37/36)

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midpoint (1/8 ,-4/9),(-5/2 , 5/2)

midpoint

(\frac{1}{8}, - \frac{4}{9}), (- \frac{5}{2}, \frac{5}{2})

(- \frac{19}{16}, \frac{37}{36})

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (\frac{1}{8}, - \frac{4}{9}), (x_{2}, y_{2}) = (- \frac{5}{2}, \frac{5}{2})

= (\frac{- \frac{5}{2} + \frac{1}{8}}{2}, \frac{\frac{5}{2} - \frac{4}{9}}{2})

Refine

= (- \frac{19}{16}, \frac{37}{36})

f (x) = 2 x^{2} - 6 x + 8

f (x) = \frac{( x ^{2} + 2 x + 1 )}{( x ^{2} + 2 x - 1 )}

y = \frac{1}{3} x - 2

- 5

4 x - 3 y = 24

What is the midpoint (1/8 ,-4/9),(-5/2 , 5/2) ?
The midpoint (1/8 ,-4/9),(-5/2 , 5/2) is (-19/16 , 37/36)