What is the critical x^3-3/2 x^2 ?

The critical x^3-3/2 x^2 is x=0,x=1

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critical x^3-3/2 x^2

critical points

x^{3} - \frac{3}{2} x^{2}

x = 0, x = 1

Solution steps

x^{3} - \frac{3}{2} x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

x^{3} - \frac{3}{2} x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 1

f (x) = - x^{2} + 3 x - 2

f (x) = \frac{( x ^{2} + 3 )}{x ^{2} + 1}

f (x) = (x - 4) 2 - 5

f (x) = \frac{9 x ^{2}}{x + 3}

\frac{x ^{2} - 2 x - 3}{x}