What is the asymptotes of f(x)=(sqrt(2x^2+1))/(x-3) ?

The asymptotes of f(x)=(sqrt(2x^2+1))/(x-3) is Vertical: x=3,Horizontal: y=sqrt(2),y=-sqrt(2)

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asymptotes of f(x)=(sqrt(2x^2+1))/(x-3)

asymptotes

f (x) = \frac{2 x ^{2} + 1}{x - 3}

Vertical : x = 3, Horizontal : y = 2, y = - 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 1}{x - 3} : x = 3

Horizontal Asymptotes of

\frac{2 x ^{2} + 1}{x - 3} : y = 2, y = - 2

Slant Asymptotes of

\frac{2 x ^{2} + 1}{x - 3} :

None

Vertical : x = 3, Horizontal : y = 2, y = - 2

(3.1) (7.1)

sin (2.8 x + 0.9) + 0.3

- x^{2} - 4 x

f (x) = \frac{2 x - 1}{x - 3}

f (x) = 3 x + 18

What is the asymptotes of f(x)=(sqrt(2x^2+1))/(x-3) ?
The asymptotes of f(x)=(sqrt(2x^2+1))/(x-3) is Vertical: x=3,Horizontal: y=sqrt(2),y=-sqrt(2)