What is the inverse of f(x)=sqrt(x^2+1) ?

The inverse of f(x)=sqrt(x^2+1) is sqrt(x^2-1),-sqrt(x^2-1)

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inverse of f(x)=sqrt(x^2+1)

inverse

f (x) = x^{2} + 1

x^{2} - 1, - x^{2} - 1

Solution steps

y = x^{2} + 1

Replace

x

with

y

x = y^{2} + 1

Solve for

y, x = y^{2} + 1

x^{2} - 1, - x^{2} - 1

f (x) = 3 x^{2} + 5 x - 12

g (x) = x - 4

y = \frac{2 x ^{2} - x - 3}{x ^{2} - 4}

\frac{\frac{2}{x}}{\frac{2}{x} + 2}

f (x) = (x + 4)

What is the inverse of f(x)=sqrt(x^2+1) ?
The inverse of f(x)=sqrt(x^2+1) is sqrt(x^2-1),-sqrt(x^2-1)