What is the inverse of f(x)= 1/2 x^3-2 ?

The inverse of f(x)= 1/2 x^3-2 is cube root of 2x+4

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inverse of f(x)= 1/2 x^3-2

inverse

f (x) = \frac{1}{2} x^{3} - 2

Solution steps

y = \frac{1}{2} x^{3} - 2

Replace

x

with

y

x = \frac{1}{2} y^{3} - 2

Solve for

y, x = \frac{1}{2} y^{3} - 2

y = - 6 (x - 4)^{2} - 1

f (x) = \frac{x ^{2}}{x + 2}

f (x) = (\frac{2}{x}) (\frac{x}{x + 2})

4 x - 3

8 y - 4 x = - 56

What is the inverse of f(x)= 1/2 x^3-2 ?
The inverse of f(x)= 1/2 x^3-2 is cube root of 2x+4