What is the critical y=((x+3))/(x^2-4) ?

The critical y=((x+3))/(x^2-4) is x=-3-sqrt(5),x=-3+sqrt(5)

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critical y=((x+3))/(x^2-4)

critical points

y = \frac{( x + 3 )}{x ^{2} - 4}

x = - 3 - 5, x = - 3 + 5

Solution steps

\frac{x + 3}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3 - 5, x = - 3 + 5, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x + 3}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{x + 3}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = - 3 - 5, x = - 3 + 5

f (x) = \frac{10000}{10 + x}

f (x) = 4 x^{3} + 3

f (x) = x^{3} + 5

(0.7288) (0.9192)

x^{2} + x - 2

What is the critical y=((x+3))/(x^2-4) ?
The critical y=((x+3))/(x^2-4) is x=-3-sqrt(5),x=-3+sqrt(5)