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Popular >

midpoint (8,3),(9.5,-3)

Solution

midpoint

(8, 3), (9.5, - 3)

Solution

(8.75, 0)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (8, 3), (x_{2}, y_{2}) = (9.5, - 3)

= (\frac{9.5 + 8}{2}, \frac{- 3 + 3}{2})

Refine

= (8.75, 0)

Popular Examples

range of f(x)=(x^3+x^2+x+1)/(|x+1|)range

f (x) = \frac{x ^{3} + x ^{2} + x + 1}{∣ x + 1 ∣}

inverse of f(x)= x/(1-x)inverse

f (x) = \frac{x}{1 - x}

inverse of x^2-7,x>= 0 inverse

x^{2} - 7, x \geq 0

asymptotes of f(x)=(2x^2-9)/(x^2-9)asymptotes

f (x) = \frac{2 x ^{2} - 9}{x ^{2} - 9}

domain of sqrt(9+x^2)domain

9 + x^{2}

Frequently Asked Questions (FAQ)

What is the midpoint (8,3),(9.5,-3) ?
The midpoint (8,3),(9.5,-3) is (8.75,0)