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Popular >

range of 2x^2+1

Solution

range

2 x^{2} + 1

Solution

f (x) \geq 1

+1

Interval Notation

[1, \infty)

Solution steps

Vertex of

2 x^{2} + 1 :

Minimum

(0, 1)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (0, 1)

f (x) \geq 1

Popular Examples

inverse of f(x)=(x+8)^3+7 inverse

f (x) = (x + 8)^{3} + 7

domain of 3/(x+2)domain

\frac{3}{x + 2}

parallel y= 1/2 x-6 parallel

y = \frac{1}{2} x - 6

domain of \sqrt[3]{x+2}domain

asymptotes of f(x)=(x^2-8x-9)/(x^3+x-2)asymptotes

f (x) = \frac{x ^{2} - 8 x - 9}{x ^{3} + x - 2}

Frequently Asked Questions (FAQ)

What is the range of 2x^2+1 ?
The range of 2x^2+1 is f(x)>= 1