What is the domain of f(x)= 1/(sqrt(x+1)) ?

The domain of f(x)= 1/(sqrt(x+1)) is x>-1

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domain of f(x)= 1/(sqrt(x+1))

domain

f (x) = \frac{1}{x + 1}

x > - 1

Interval Notation

(- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

Find undefined (singularity) points:

x = - 1

Combine real regions and undefined points for final function domain

x > - 1

y = - x + 4

f (x) = x^{2} - x

(3, - 7), (- 10, - 2)

(- 4, 5), (- 1, - 4)

f (x) = 196 - x^{2}

What is the domain of f(x)= 1/(sqrt(x+1)) ?
The domain of f(x)= 1/(sqrt(x+1)) is x>-1