What is the domain of (5x)/(x^2-9) ?

The domain of (5x)/(x^2-9) is x 3

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domain of (5x)/(x^2-9)

domain

\frac{5 x}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = \frac{( x - 4 ) x + 2}{x ^{2}}

f (x) = \frac{x ^{3}}{( x - 1 ) ^{2}}

f (x) = \frac{1}{1 - x}

2 x^{2} + 3

f (x) = x e^{x}

What is the domain of (5x)/(x^2-9) ?
The domain of (5x)/(x^2-9) is x<-3\lor-3<x<3\lor x>3