What is the inverse of y=sqrt(x^2+2) ?

The inverse of y=sqrt(x^2+2) is sqrt(x^2-2),-sqrt(x^2-2)

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inverse of y=sqrt(x^2+2)

inverse

y = x^{2} + 2

x^{2} - 2, - x^{2} - 2

Solution steps

y = x^{2} + 2

Replace

x

with

y

x = y^{2} + 2

Solve for

y, x = y^{2} + 2

x^{2} - 2, - x^{2} - 2

f (x) = \frac{3 x - 4}{x - 2}

3^{x} - 2

f (x) = \frac{4}{3} x + 4

f (x) = 12 \cdot \frac{x + 9}{2}

\frac{2 x - 9}{- 4 x + 1}

What is the inverse of y=sqrt(x^2+2) ?
The inverse of y=sqrt(x^2+2) is sqrt(x^2-2),-sqrt(x^2-2)