What is the inverse of f(x)=(-6-\sqrt[3]{4x})/2 ?

The inverse of f(x)=(-6-\sqrt[3]{4x})/2 is -2(x^3+9x^2+27x+27)

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inverse of f(x)=(-6-\sqrt[3]{4x})/2

inverse

- 2 (x^{3} + 9 x^{2} + 27 x + 27)

Solution steps

Replace

x

with

y

Solve for

- 2 (x^{3} + 9 x^{2} + 27 x + 27)

y = - \frac{5}{6} x - 5, (- 8, 9)

f (x) = \frac{\frac{5}{x}}{\frac{5}{x} + 5}

(3, 8), (0, 2)

x^{4} e^{- \frac{x}{2}}

\frac{3}{x}

What is the inverse of f(x)=(-6-\sqrt[3]{4x})/2 ?
The inverse of f(x)=(-6-\sqrt[3]{4x})/2 is -2(x^3+9x^2+27x+27)