What is the inverse of f(x)=3\sqrt[3]{x}-2 ?

The inverse of f(x)=3\sqrt[3]{x}-2 is (x^3}{27}+\frac{2x^2)/9+(4x)/9+8/27

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inverse of f(x)=3\sqrt[3]{x}-2

inverse

\frac{x ^{3}}{27} + \frac{2 x ^{2}}{9} + \frac{4 x}{9} + \frac{8}{27}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{27} + \frac{2 x ^{2}}{9} + \frac{4 x}{9} + \frac{8}{27}

y = 2 - x + 1

- \frac{1}{2} (x + 1)^{2} - 3

f (x) = ln (x - 1) - ln (x)

12 x^{2} - x^{3}

y = x - 5

What is the inverse of f(x)=3\sqrt[3]{x}-2 ?
The inverse of f(x)=3\sqrt[3]{x}-2 is (x^3}{27}+\frac{2x^2)/9+(4x)/9+8/27