What is the domain of f(x)=sqrt(-42+19x-2x^2) ?

The domain of f(x)=sqrt(-42+19x-2x^2) is 7/2 <= x<= 6

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domain of f(x)=sqrt(-42+19x-2x^2)

domain

f (x) = - 42 + 19 x - 2 x^{2}

\frac{7}{2} \leq x \leq 6

Interval Notation

[\frac{7}{2}, 6]

Solution steps

Find non-negative values for radicals:

\frac{7}{2} \leq x \leq 6

The function domain

\frac{7}{2} \leq x \leq 6

(x - 5)^{\frac{2}{3}}

f (x) = \frac{tan ( x )}{4 - x ^{2}}

f (x) = 0. 5^{x}

f (x) = \frac{2 x ^{2} - 3}{5}

f (x) = 4 x^{3} - 48 x

What is the domain of f(x)=sqrt(-42+19x-2x^2) ?
The domain of f(x)=sqrt(-42+19x-2x^2) is 7/2 <= x<= 6