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Popular >

distance (4,-3),(0,1)

Solution

distance

(4, - 3), (0, 1)

Solution

42

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(4, - 3)

and

(0, 1)

is

= (0 - 4)^{2} + (1 - (- 3))^{2}

Simplify

= 42

Popular Examples

inverse of f(x)=4x+2ln(3)inverse

f (x) = 4 x + 2 ln (3)

domain of f(x)=x^2-4x^3 domain

f (x) = x^{2} - 4 x^{3}

intercepts of f(x)=x^3-3x^2+2 intercepts

f (x) = x^{3} - 3 x^{2} + 2

range of x/(x^2+x-6)range

\frac{x}{x ^{2} + x - 6}

asymptotes of f(x)=((12x-3))/((9x^2-4))asymptotes

f (x) = \frac{( 12 x - 3 )}{( 9 x ^{2} - 4 )}

Frequently Asked Questions (FAQ)

What is the distance (4,-3),(0,1) ?
The distance (4,-3),(0,1) is 4sqrt(2)