en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)=(x-3)^2+5

Solution

range

f (x) = (x - 3)^{2} + 5

Solution

f (x) \geq 5

+1

Solution steps

Vertex of

(x - 3)^{2} + 5 :

Minimum

(3, 5)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 1,

Vertex

(x_{v}, y_{v}) = (3, 5)

f (x) \geq 5

Popular Examples

critical f(x)=3x^4+4x^3 critical points

f (x) = 3 x^{4} + 4 x^{3}

range of f(x)=log_{1/20}(-x)range

f (x) = lo g_{\frac{1}{20}} (- x)

line m= 15/1 ,(1,8)line

m = \frac{15}{1}, (1, 8)

asymptotes of f(x)= 6/(x-5)asymptotes

f (x) = \frac{6}{x - 5}

inverse of f(x)=2y^2 inverse

f (x) = 2 y^{2}

Frequently Asked Questions (FAQ)

What is the range of f(x)=(x-3)^2+5 ?
The range of f(x)=(x-3)^2+5 is f(x)>= 5