What is the inverse of f(x)=(x-4)^2+2,x>= 4 ?

The inverse of f(x)=(x-4)^2+2,x>= 4 is sqrt(x-2)+4,-sqrt(x-2)+4

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inverse of f(x)=(x-4)^2+2,x>= 4

inverse

f (x) = (x - 4)^{2} + 2, x \geq 4

x - 2 + 4, - x - 2 + 4

Solution steps

y = (x - 4)^{2} + 2

Replace

x

with

y

x = (y - 4)^{2} + 2

Solve for

y, x = (y - 4)^{2} + 2

x - 2 + 4, - x - 2 + 4

f (x) = \frac{x ^{2} + 1}{x + 1}

6 x^{3} + 45 x^{2} - 108 x + 6

f (x) = \frac{3 x}{x ^{2} - 4}

e^{t} - t

\frac{5}{2 5 x + 6}

What is the inverse of f(x)=(x-4)^2+2,x>= 4 ?
The inverse of f(x)=(x-4)^2+2,x>= 4 is sqrt(x-2)+4,-sqrt(x-2)+4