What is the domain of f(x)=x-4= 3/(y+1) ?

The domain of f(x)=x-4= 3/(y+1) is y -1

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domain of f(x)=x-4= 3/(y+1)

domain

f (x) = x - 4 = \frac{3}{y + 1}

y < - 1 or y > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

y = - 1

The function domain

y < - 1 or y > - 1

- x^{2} - 2 x - 5

- x^{2} - 4 x + 5

- x - 1

f (x) = \frac{2 x}{x ^{2} + 2 x + 1}

(x - 1)^{2} - 4

What is the domain of f(x)=x-4= 3/(y+1) ?
The domain of f(x)=x-4= 3/(y+1) is y<-1\lor y>-1