Solution
midpoint
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f(x)=x^2+xparity y=sin(sqrt(cos(tan(pix))))parity distance (-4,5),(7,18)distance extreme f(x)=(x-4)^2extreme points symmetry x^2+y^2+6x-2y-15=0symmetry
Frequently Asked Questions (FAQ)
What is the midpoint (-1,4),(4,-2) ?
The midpoint (-1,4),(4,-2) is (3/2 ,1)