What is the inflection (2+x-x^2)/((x-1)^2) ?

The inflection (2+x-x^2)/((x-1)^2) is (7,-10/9)

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inflection (2+x-x^2)/((x-1)^2)

inflection points

\frac{2 + x - x ^{2}}{( x - 1 ) ^{2}}

(7, - \frac{10}{9})

Solution steps

f^{''} (x) = \frac{2 ( - x + 7 )}{( x - 1 ) ^{4}}

Find intervals:

Concave Upward

: - \infty < x < 1,

Concave Upward

: 1 < x < 7,

Concave Downward

: 7 < x < \infty

Plug

x = 7

into

\frac{2 + x - x ^{2}}{( x - 1 ) ^{2}} : - \frac{10}{9}

(7, - \frac{10}{9})

2 cos (2 x) - 1

(- 8, 1), (- 5, 6)

f (x) = 3 (\frac{1}{2})^{x}

f (x) = x^{2} + 4 x + 2

y - 7 = 0

What is the inflection (2+x-x^2)/((x-1)^2) ?
The inflection (2+x-x^2)/((x-1)^2) is (7,-10/9)