What is the critical f(x)=x^4-32x^2+256 ?

The critical f(x)=x^4-32x^2+256 is x=-4,x=0,x=4

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critical f(x)=x^4-32x^2+256

critical points

f (x) = x^{4} - 32 x^{2} + 256

x = - 4, x = 0, x = 4

Solution steps

x^{4} - 32 x^{2} + 256

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 0, x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{4} - 32 x^{2} + 256 : - \infty < x < \infty

All critical points are in domain

x = - 4, x = 0, x = 4

f (x) = 7 x^{3} - 2

f (x) = 4 x^{2} - 4 x + 21

f (x) = - 16 t^{2} + 60 t + 2

f (x) = x^{4} + 2 x^{3} + 2 x^{2} + x

f (x) = \frac{2}{x + 5}

What is the critical f(x)=x^4-32x^2+256 ?
The critical f(x)=x^4-32x^2+256 is x=-4,x=0,x=4