What is the asymptotes of f(x)=(9x^2+7x)/(x^4-1) ?

The asymptotes of f(x)=(9x^2+7x)/(x^4-1) is Vertical: x=-1,x=1,Horizontal: y=0

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asymptotes of f(x)=(9x^2+7x)/(x^4-1)

asymptotes

f (x) = \frac{9 x ^{2} + 7 x}{x ^{4} - 1}

Vertical : x = - 1, x = 1, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{9 x ^{2} + 7 x}{x ^{4} - 1} : x = - 1, x = 1

Horizontal Asymptotes of

\frac{9 x ^{2} + 7 x}{x ^{4} - 1} : y = 0

Slant Asymptotes of

\frac{9 x ^{2} + 7 x}{x ^{4} - 1} :

None

Vertical : x = - 1, x = 1, Horizontal : y = 0

f (x) = - \frac{3}{2 - 4 x}

f (x) = 4 + x^{2}

f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2}

m = - 10, (0, 0)

(- 1, 5), (9, - 1)

What is the asymptotes of f(x)=(9x^2+7x)/(x^4-1) ?
The asymptotes of f(x)=(9x^2+7x)/(x^4-1) is Vertical: x=-1,x=1,Horizontal: y=0