What is the critical f(x)=3x^5-5x^3+1 ?

The critical f(x)=3x^5-5x^3+1 is x=-1,x=0,x=1

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critical f(x)=3x^5-5x^3+1

critical points

f (x) = 3 x^{5} - 5 x^{3} + 1

x = - 1, x = 0, x = 1

Solution steps

3 x^{5} - 5 x^{3} + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 1

Identify critical points not in

f (x)

domain

Domain of

3 x^{5} - 5 x^{3} + 1 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 1

(x - 3)^{2} - 9

f (x) = cos (x)

f (x) = \frac{1}{9} x^{2}

f (x) = - 3 - 2 x - 7

What is the critical f(x)=3x^5-5x^3+1 ?
The critical f(x)=3x^5-5x^3+1 is x=-1,x=0,x=1