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Popular >

distance (2,-3),(0,-8)

Solution

distance

(2, - 3), (0, - 8)

Solution

29

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(2, - 3)

and

(0, - 8)

is

= (0 - 2)^{2} + (- 8 - (- 3))^{2}

Simplify

= 29

Popular Examples

inverse of 1/(4x)inverse

\frac{1}{4 x}

domain of x^2-8x+7 domain

x^{2} - 8 x + 7

perpendicular y=x+10,(3,-6)perpendicular

y = x + 10, (3, - 6)

monotone x^2-4 monotone intervals

x^{2} - 4

inverse of y=x+6 inverse

y = x + 6

Frequently Asked Questions (FAQ)

What is the distance (2,-3),(0,-8) ?
The distance (2,-3),(0,-8) is square root of 29