What is the critical f(x)=x^3+3x^2+x ?

The critical f(x)=x^3+3x^2+x is x=-(3+sqrt(6))/3 ,x=(-3+sqrt(6))/3

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critical f(x)=x^3+3x^2+x

critical points

f (x) = x^{3} + 3 x^{2} + x

x = - \frac{3 + 6}{3}, x = \frac{- 3 + 6}{3}

Solution steps

x^{3} + 3 x^{2} + x

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3 + 6}{3}, x = \frac{- 3 + 6}{3}

Identify critical points not in

f (x)

domain

Domain of

x^{3} + 3 x^{2} + x : - \infty < x < \infty

All critical points are in domain

x = - \frac{3 + 6}{3}, x = \frac{- 3 + 6}{3}

(20.8) (40.7)

f (x) = x^{2} - 3 x - 28

16 x - 4 y = - 20

y = \frac{1}{5} x - 7

- 5 + ∣ x - 2 ∣

What is the critical f(x)=x^3+3x^2+x ?
The critical f(x)=x^3+3x^2+x is x=-(3+sqrt(6))/3 ,x=(-3+sqrt(6))/3