What is the domain of (4x+1)/(x^2+x-56) ?

The domain of (4x+1)/(x^2+x-56) is x 7

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domain of (4x+1)/(x^2+x-56)

domain

\frac{4 x + 1}{x ^{2} + x - 56}

x < - 8 or - 8 < x < 7 or x > 7

Interval Notation

(- \infty, - 8) \cup (- 8, 7) \cup (7, \infty)

Solution steps

Find undefined (singularity) points:

x = 7, x = - 8

The function domain

x < - 8 or - 8 < x < 7 or x > 7

f (x) = \frac{x ^{2} - 1}{x ^{2} + 1}

y = 3 x^{2} + 8 x - 3

f (x) = 4 x^{2} + 3

5, - 6

f (x) = - 3^{x} + 4

What is the domain of (4x+1)/(x^2+x-56) ?
The domain of (4x+1)/(x^2+x-56) is x<-8\lor-8<x<7\lor x>7