What is the critical f(x)= 1/2 x^2+8x+5 ?

The critical f(x)= 1/2 x^2+8x+5 is x=-8

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critical f(x)= 1/2 x^2+8x+5

critical points

f (x) = \frac{1}{2} x^{2} + 8 x + 5

x = - 8

Solution steps

\frac{1}{2} x^{2} + 8 x + 5

Find where

f^{'} (x)

is equal to zero or undefined

x = - 8

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{2} x^{2} + 8 x + 5 : - \infty < x < \infty

All critical points are in domain

x = - 8

f (x) = 5 x

f (x) = \frac{x + 1}{x ^{2} + 8}

f (x) = \frac{8}{10 + x}

2 (x + 3)^{3} + 4

y = \frac{2}{5}

What is the critical f(x)= 1/2 x^2+8x+5 ?
The critical f(x)= 1/2 x^2+8x+5 is x=-8