What is the extreme f(x)=x^3-5x^2-8x+5 ?

The extreme f(x)=x^3-5x^2-8x+5 is Maximum(-2/3 , 211/27),Minimum(4,-43)

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extreme f(x)=x^3-5x^2-8x+5

extreme points

f (x) = x^{3} - 5 x^{2} - 8 x + 5

Maximum (- \frac{2}{3}, \frac{211}{27}), Minimum (4, - 43)

Solution steps

f^{'} (x) = 3 x^{2} - 10 x - 8

Find intervals:

Increasing

: - \infty < x < - \frac{2}{3},

Decreasing

: - \frac{2}{3} < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - \frac{2}{3}

into

x^{3} - 5 x^{2} - 8 x + 5 : \frac{211}{27}

Maximum (- \frac{2}{3}, \frac{211}{27})

Plug

x = 4

into

x^{3} - 5 x^{2} - 8 x + 5 : - 43

Minimum (4, - 43)

Maximum (- \frac{2}{3}, \frac{211}{27}), Minimum (4, - 43)

5 x^{2} - 4 x + 3

f (x) = 6 x^{4}

f (x) = x - 8

f (x) = 3 x + 14

3 (\frac{1}{8})^{x}

What is the extreme f(x)=x^3-5x^2-8x+5 ?
The extreme f(x)=x^3-5x^2-8x+5 is Maximum(-2/3 , 211/27),Minimum(4,-43)