What is the range of f(x)=sqrt(3-x) ?

The range of f(x)=sqrt(3-x) is f(x)>= 0

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range of f(x)=sqrt(3-x)

range

f (x) = 3 - x

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = \frac{( x - 1 ) ^{3}}{x ^{2}}

f (x) = lo g_{3} (x + 1)

f (x) = 5 x^{2} + 10 x + 3

(- 3, 0), (0, 5)

f (x) = \frac{3 x - 15}{- x ^{2} + 5 x}