What is the domain of f(x)=(4x^2-1)/(2x-1) ?

The domain of f(x)=(4x^2-1)/(2x-1) is x 1/2

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domain of f(x)=(4x^2-1)/(2x-1)

domain

f (x) = \frac{4 x ^{2} - 1}{2 x - 1}

x < \frac{1}{2} or x > \frac{1}{2}

Interval Notation

(- \infty, \frac{1}{2}) \cup (\frac{1}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{1}{2}

The function domain

x < \frac{1}{2} or x > \frac{1}{2}

ln (1 + x^{2})

(\frac{3}{4}, - \frac{2}{5}), (- \frac{1}{8}, \frac{3}{2})

f (x) = 6 x - 42

\frac{x ^{2}}{x ^{2} + 3}

\frac{( x ^{2} )}{x ^{2} - 16}

What is the domain of f(x)=(4x^2-1)/(2x-1) ?
The domain of f(x)=(4x^2-1)/(2x-1) is x< 1/2 \lor x> 1/2