What is the domain of f(x)= 2/3 sqrt(x+1)-4 ?

The domain of f(x)= 2/3 sqrt(x+1)-4 is x>=-1

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domain of f(x)= 2/3 sqrt(x+1)-4

domain

f (x) = \frac{2}{3} x + 1 - 4

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

f (x) = \frac{( 5 x + 2 )}{x - 3}

2 y - 10 x = - 6

f (x) = \frac{10}{x ^{2} + 5}

f (x) = (\frac{3 x}{2})^{\frac{2}{3}}

x^{4} + x^{3} - 3 x^{2} + 1

What is the domain of f(x)= 2/3 sqrt(x+1)-4 ?
The domain of f(x)= 2/3 sqrt(x+1)-4 is x>=-1