What is the domain of f(x)=sqrt(x^2)+1 ?

The domain of f(x)=sqrt(x^2)+1 is -infinity <x<infinity

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domain of f(x)=sqrt(x^2)+1

domain

f (x) = x^{2} + 1

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < x < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

x^{2} - 3 x + 2

f (x) = 3 + 2 sin (6 x + \frac{π}{4})

(\frac{1}{2} x - 1)^{2} - 2

f (x) = x + 25

f (x) = x^{2} - 4 x - 5

What is the domain of f(x)=sqrt(x^2)+1 ?
The domain of f(x)=sqrt(x^2)+1 is -infinity <x<infinity