What is the domain of f(x)=(2x+5)/(x^3+x^2-9x-9) ?

The domain of f(x)=(2x+5)/(x^3+x^2-9x-9) is x 3

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domain of f(x)=(2x+5)/(x^3+x^2-9x-9)

domain

f (x) = \frac{2 x + 5}{x ^{3} + x ^{2} - 9 x - 9}

x < - 3 or - 3 < x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1, x = - 3, x = 3

The function domain

x < - 3 or - 3 < x < - 1 or - 1 < x < 3 or x > 3

f (x) = - 4.9 (x + 3)^{2} + 45.8

f (x) = \frac{x ^{2} + 16}{x ( 3 x - 6 )}

f (x) = \frac{3}{x ^{2} - 4}

\frac{4 x + 1}{4 x + 4}

5 x^{2} - 3 x

What is the domain of f(x)=(2x+5)/(x^3+x^2-9x-9) ?
The domain of f(x)=(2x+5)/(x^3+x^2-9x-9) is x<-3\lor-3<x<-1\lor-1<x<3\lor x>3