What is the domain of f(x)=(x^3-9x)/(3x^2-6x-9) ?

The domain of f(x)=(x^3-9x)/(3x^2-6x-9) is x 3

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domain of f(x)=(x^3-9x)/(3x^2-6x-9)

domain

f (x) = \frac{x ^{3} - 9 x}{3 x ^{2} - 6 x - 9}

x < - 1 or - 1 < x < 3 or x > 3

Interval Notation

(- \infty, - 1) \cup (- 1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 1

The function domain

x < - 1 or - 1 < x < 3 or x > 3

f (x) = \frac{6}{9 - x}

\frac{2}{x - 3}

\frac{s + 1}{s ^{3} + 4 s ^{2} + 2 s + 3}

f (x) = 4 x^{3} - 3 x^{2} + 8

f (x) = \frac{( x - 9 )}{( x - 2 )}

What is the domain of f(x)=(x^3-9x)/(3x^2-6x-9) ?
The domain of f(x)=(x^3-9x)/(3x^2-6x-9) is x<-1\lor-1<x<3\lor x>3