What is the inverse of f(x)=((x-9))/((x-2)) ?

The inverse of f(x)=((x-9))/((x-2)) is (-9+2x)/(x-1)

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inverse of f(x)=((x-9))/((x-2))

inverse

f (x) = \frac{( x - 9 )}{( x - 2 )}

\frac{- 9 + 2 x}{x - 1}

Solution steps

y = \frac{x - 9}{x - 2}

Replace

x

with

y

x = \frac{y - 9}{y - 2}

Solve for

y, x = \frac{y - 9}{y - 2}

\frac{- 9 + 2 x}{x - 1}

\frac{2}{x} + 4

5 x + 3 y = 2

\frac{x + 5}{x ^{2} - 25}

f (x) = x^{2} - 2 x + 2

y = 4 x + 6

What is the inverse of f(x)=((x-9))/((x-2)) ?
The inverse of f(x)=((x-9))/((x-2)) is (-9+2x)/(x-1)