What is the inverse of f(x)=3x^2+2 ?

The inverse of f(x)=3x^2+2 is sqrt((x-2)/3),-sqrt((x-2)/3)

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inverse of f(x)=3x^2+2

inverse

f (x) = 3 x^{2} + 2

\frac{x - 2}{3}, - \frac{x - 2}{3}

Solution steps

y = 3 x^{2} + 2

Replace

x

with

y

x = 3 y^{2} + 2

Solve for

y, x = 3 y^{2} + 2

\frac{x - 2}{3}, - \frac{x - 2}{3}

f (x) = \frac{4 x - 8}{3}

h (x) = 4^{x}

y = \frac{1}{3} x - 3

8 x - 5 y + 13 = 0

f (x) = \frac{( x + 2 )}{6 x ^{2} + x - 2}

What is the inverse of f(x)=3x^2+2 ?
The inverse of f(x)=3x^2+2 is sqrt((x-2)/3),-sqrt((x-2)/3)