What is the asymptotes of f(x)=(16)/(x^2-2x-8) ?

The asymptotes of f(x)=(16)/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=0

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asymptotes of f(x)=(16)/(x^2-2x-8)

asymptotes

f (x) = \frac{16}{x ^{2} - 2 x - 8}

Vertical : x = - 2, x = 4, Horizontal : y = 0

Solution steps

Vertical asymptotes of

\frac{16}{x ^{2} - 2 x - 8} : x = - 2, x = 4

Horizontal Asymptotes of

\frac{16}{x ^{2} - 2 x - 8} : y = 0

Slant Asymptotes of

\frac{16}{x ^{2} - 2 x - 8} :

None

Vertical : x = - 2, x = 4, Horizontal : y = 0

f (x) = \frac{x ^{2} - 9}{x}

f (x) = \frac{x ^{2} - 2 x - 3}{x - 3}

(- 7, - 1), (- 7, 9)

f (x) = \frac{1}{4} x - 2

f (x) = {- x^{2}, x < 0}

What is the asymptotes of f(x)=(16)/(x^2-2x-8) ?
The asymptotes of f(x)=(16)/(x^2-2x-8) is Vertical: x=-2,x=4,Horizontal: y=0