What is the domain of sqrt(t^2+1) ?

The domain of sqrt(t^2+1) is -infinity <t<infinity

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domain of sqrt(t^2+1)

domain

t^{2} + 1

- \infty < t < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find non-negative values for radicals:

- \infty < t < \infty

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < t < \infty

- x^{2} + 2 x + 17

y = 11 x

g (x) = x + 4

(4, 4), (- 2, - 2)

f (x) = 5 x^{2} + x - 4

What is the domain of sqrt(t^2+1) ?
The domain of sqrt(t^2+1) is -infinity <t<infinity