What is the inverse of f(x)=-2(x-1)^2+3 ?

The inverse of f(x)=-2(x-1)^2+3 is sqrt(-(x-3)/2)+1,-sqrt(-(x-3)/2)+1

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inverse of f(x)=-2(x-1)^2+3

inverse

f (x) = - 2 (x - 1)^{2} + 3

- \frac{x - 3}{2} + 1, - - \frac{x - 3}{2} + 1

Solution steps

y = - 2 (x - 1)^{2} + 3

Replace

x

with

y

x = - 2 (y - 1)^{2} + 3

Solve for

y, x = - 2 (y - 1)^{2} + 3

- \frac{x - 3}{2} + 1, - - \frac{x - 3}{2} + 1

3 y = - 9 x + 13

f (x) = 8 x^{2} + 1

x^{2} - 6 x + 8

f (x) = \frac{x}{x - 9}

f (x) = 3 x^{2} - 2 x - 5

What is the inverse of f(x)=-2(x-1)^2+3 ?
The inverse of f(x)=-2(x-1)^2+3 is sqrt(-(x-3)/2)+1,-sqrt(-(x-3)/2)+1