What is the domain of f(x)= 1/(sqrt(2x+1)) ?

The domain of f(x)= 1/(sqrt(2x+1)) is x>-1/2

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domain of f(x)= 1/(sqrt(2x+1))

domain

f (x) = \frac{1}{2 x + 1}

x > - \frac{1}{2}

Interval Notation

(- \frac{1}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - \frac{1}{2}

Find undefined (singularity) points:

x = - \frac{1}{2}

Combine real regions and undefined points for final function domain

x > - \frac{1}{2}

f (x) = 2 x^{2} - 2

\frac{6}{x - 5}

g (x) = \frac{5}{2} x + 4

f (x) = \frac{x - 6}{x + 3}

x + 4 y = 28

What is the domain of f(x)= 1/(sqrt(2x+1)) ?
The domain of f(x)= 1/(sqrt(2x+1)) is x>-1/2