What is the critical x^3-6x^2 ?

The critical x^3-6x^2 is x=0,x=4

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critical x^3-6x^2

critical points

x^{3} - 6 x^{2}

x = 0, x = 4

Solution steps

x^{3} - 6 x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 4

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 6 x^{2} : - \infty < x < \infty

All critical points are in domain

x = 0, x = 4

(8, 3), (2, 5)

f (x) = x^{2} + 2

\frac{( 1 )}{x - 5}

x + 2 y = 8

f (x) = 15 - 3 x