What is the domain of f(x)= 5/(x^2-9) ?

The domain of f(x)= 5/(x^2-9) is x 3

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domain of f(x)= 5/(x^2-9)

domain

f (x) = \frac{5}{x ^{2} - 9}

x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

(- \infty, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 3

The function domain

x < - 3 or - 3 < x < 3 or x > 3

f (x) = x^{2} - 3 x + 4

f (x) = \frac{1}{2} x^{2} - 2

(- 7, 0), (0, - 8)

y = 2 + lo g_{3} (x)

What is the domain of f(x)= 5/(x^2-9) ?
The domain of f(x)= 5/(x^2-9) is x<-3\lor-3<x<3\lor x>3