What is the extreme f(x)=x^3-6x^2+9 ?

The extreme f(x)=x^3-6x^2+9 is Maximum(0,9),Minimum(4,-23)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-6x^2+9

extreme points

f (x) = x^{3} - 6 x^{2} + 9

Maximum (0, 9), Minimum (4, - 23)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 0

into

x^{3} - 6 x^{2} + 9 : 9

Maximum (0, 9)

Plug

x = 4

into

x^{3} - 6 x^{2} + 9 : - 23

Minimum (4, - 23)

Maximum (0, 9), Minimum (4, - 23)

f (x) = \frac{x}{3 - x}

f (x) = \frac{38}{41 - x}

f (x) = 3 - 2 x

\frac{4 x - 1}{2 x + 3}

f (x) = 10 - 2 x

What is the extreme f(x)=x^3-6x^2+9 ?
The extreme f(x)=x^3-6x^2+9 is Maximum(0,9),Minimum(4,-23)