What is the domain of f(x)=sqrt(4-2x) ?

The domain of f(x)=sqrt(4-2x) is x<= 2

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domain of f(x)=sqrt(4-2x)

domain

f (x) = 4 - 2 x

x \leq 2

Interval Notation

(- \infty, 2]

Solution steps

Find non-negative values for radicals:

x \leq 2

The function domain

x \leq 2

f (x) = x^{3} - 4 x^{2} + x + 6

f (x) = 3 sin (2 x - 1) + 4

\frac{1}{2} + x + \frac{25}{4}

f (x) = \frac{x ^{2} - 12 x + 20}{x - 10}