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Popular >

distance (8,2),(4,5)

Solution

distance

(8, 2), (4, 5)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(8, 2)

and

(4, 5)

is

= (4 - 8)^{2} + (5 - 2)^{2}

Simplify

= 5

Popular Examples

asymptotes of f(x)=(x^3)/(x^2+x-4)asymptotes

f (x) = \frac{x ^{3}}{x ^{2} + x - 4}

periodicity of f(x)=cos(10x)periodicity

f (x) = cos (10 x)

domain of 3x+2 domain

3 x + 2

asymptotes of tan(x)-4 asymptotes

tan (x) - 4

domain of (sqrt(5-x))^2+4 domain

(5 - x)^{2} + 4

Frequently Asked Questions (FAQ)

What is the distance (8,2),(4,5) ?
The distance (8,2),(4,5) is 5