What is the critical 4x^3-24x^2+36x ?

The critical 4x^3-24x^2+36x is x=1,x=3

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critical 4x^3-24x^2+36x

critical points

4 x^{3} - 24 x^{2} + 36 x

x = 1, x = 3

Solution steps

4 x^{3} - 24 x^{2} + 36 x

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

4 x^{3} - 24 x^{2} + 36 x : - \infty < x < \infty

All critical points are in domain

x = 1, x = 3

\frac{x - 4}{5 - x}

\frac{x ^{3} + 3 x ^{2} + 2 x}{- 4 x ^{2} + 4 x + 8}

x^{x^{x + x^{x}}}

f (x) = - 2 x^{2} - 4 x + 48

f (x) = \frac{9}{x ^{2}}