What is the inverse of f(x)=((6x^3+3))/((-8x^3+8)) ?

The inverse of f(x)=((6x^3+3))/((-8x^3+8)) is -\sqrt[3]{(3-8x)/(2(3+4x))}

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inverse of f(x)=((6x^3+3))/((-8x^3+8))

inverse

f (x) = \frac{( 6 x ^{3} + 3 )}{( - 8 x ^{3} + 8 )}

Solution steps

y = \frac{6 x ^{3} + 3}{- 8 x ^{3} + 8}

Replace

x

with

y

x = \frac{6 y ^{3} + 3}{- 8 y ^{3} + 8}

Solve for

y, x = \frac{6 y ^{3} + 3}{- 8 y ^{3} + 8}

f (x) = \frac{x + 2}{x - 5}

f (x) = \frac{8 x + 5}{x ^{2} - 6 x - 27}

\frac{( x + 1 )}{x - 1}

f (x) = 20 x^{4} - 120 x^{2}

(1, - 1), (- 4, 4)

What is the inverse of f(x)=((6x^3+3))/((-8x^3+8)) ?
The inverse of f(x)=((6x^3+3))/((-8x^3+8)) is -\sqrt[3]{(3-8x)/(2(3+4x))}