What is the inverse of f(x)=4x^2-2 ?

The inverse of f(x)=4x^2-2 is (sqrt(x+2))/2 ,-(sqrt(x+2))/2

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inverse of f(x)=4x^2-2

inverse

f (x) = 4 x^{2} - 2

\frac{x + 2}{2}, - \frac{x + 2}{2}

Solution steps

y = 4 x^{2} - 2

Replace

x

with

y

x = 4 y^{2} - 2

Solve for

y, x = 4 y^{2} - 2

\frac{x + 2}{2}, - \frac{x + 2}{2}

\frac{x ^{2} + 2 x - 4}{5 x ^{4} - 2 x ^{3} - 7 x ^{2} - 39}

f (x) = x^{3} - 4

cos^{2} (x)

\frac{x ^{2} - 1}{x ^{3}}

f (x) = - 3 + 6 x - x^{3}

What is the inverse of f(x)=4x^2-2 ?
The inverse of f(x)=4x^2-2 is (sqrt(x+2))/2 ,-(sqrt(x+2))/2